我设法使用基于HTML的地理位置来获取用户的纬度和经度。
//Check if browser supports W3C Geolocation API
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
}
//Get latitude and longitude;
function successFunction(position) {
var lat = position.coords.latitude;
var long = position.coords.longitude;
}
我想显示城市名称,似乎获得城市名称的唯一方法是使用反向地理位置API。我阅读了Google的反向地理位置文档,但是我不知道如何在我的网站上获得输出。
我不知道该如何使用:"http://maps.googleapis.com/maps/api/geocode/json?latlng='+lat+','+long+'&sensor=true"
在页面上显示城市名称。
我该如何实现?
您将使用Google API执行类似的操作。
请注意,您必须包括google maps库才能起作用。Google地理编码器会返回很多地址组成部分,因此您必须做出有根据的猜测,以了解哪个城市将拥有该城市。
“ administrative_area_level_1”通常是您要寻找的,但有时所在地是您追求的城市。
无论如何-有关Google响应类型的更多详细信息,请参见此处和此处。
下面是应该完成此操作的代码:
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no"/>
<meta http-equiv="content-type" content="text/html; charset=UTF-8"/>
<title>Reverse Geocoding</title>
<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
var geocoder;
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
}
//Get the latitude and the longitude;
function successFunction(position) {
var lat = position.coords.latitude;
var lng = position.coords.longitude;
codeLatLng(lat, lng)
}
function errorFunction(){
alert("Geocoder failed");
}
function initialize() {
geocoder = new google.maps.Geocoder();
}
function codeLatLng(lat, lng) {
var latlng = new google.maps.LatLng(lat, lng);
geocoder.geocode({'latLng': latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
console.log(results)
if (results[1]) {
//formatted address
alert(results[0].formatted_address)
//find country name
for (var i=0; i<results[0].address_components.length; i++) {
for (var b=0;b<results[0].address_components[i].types.length;b++) {
//there are different types that might hold a city admin_area_lvl_1 usually does in come cases looking for sublocality type will be more appropriate
if (results[0].address_components[i].types[b] == "administrative_area_level_1") {
//this is the object you are looking for
city= results[0].address_components[i];
break;
}
}
}
//city data
alert(city.short_name + " " + city.long_name)
} else {
alert("No results found");
}
} else {
alert("Geocoder failed due to: " + status);
}
});
}
</script>
</head>
<body onload="initialize()">
</body>
</html>
$.ajax({
url: "https://geolocation-db.com/jsonp",
jsonpCallback: "callback",
dataType: "jsonp",
success: function(location) {
$('#country').html(location.country_name);
$('#state').html(location.state);
$('#city').html(location.city);
$('#latitude').html(location.latitude);
$('#longitude').html(location.longitude);
$('#ip').html(location.IPv4);
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<div>Country: <span id="country"></span></div>
<div>State: <span id="state"></span></div>
<div>City: <span id="city"></span></div>
<div>Latitude: <span id="latitude"></span></div>
<div>Longitude: <span id="longitude"></span></div>
<div>IP: <span id="ip"></span></div>
使用html5地理位置需要用户许可。如果您不想这样做,请使用外部定位器,例如https://geolocation-db.com。支持IPv6。没有限制和无限的请求。
例
对于不使用jQuery的纯JavaScript示例,请查看此答案。
另一种方法是使用我的服务http://ipinfo.io,该服务根据用户的当前IP地址返回城市,地区和国家/地区名称。这是一个简单的例子:
$.get("http://ipinfo.io", function(response) {
console.log(response.city, response.country);
}, "jsonp");
这是一个更详细的JSFiddle示例,该示例还打印了完整的响应信息,因此您可以看到所有可用的详细信息:http : //jsfiddle.net/zK5FN/2/
您可以使用Google Maps Geocoding API获取城市,国家/地区,街道名称和其他地理数据的名称
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title></title>
<script type="text/javascript" src="https://code.jquery.com/jquery-2.2.3.js"></script>
</head>
<body>
<script type="text/javascript">
navigator.geolocation.getCurrentPosition(success, error);
function success(position) {
console.log(position.coords.latitude)
console.log(position.coords.longitude)
var GEOCODING = 'https://maps.googleapis.com/maps/api/geocode/json?latlng=' + position.coords.latitude + '%2C' + position.coords.longitude + '&language=en';
$.getJSON(GEOCODING).done(function(location) {
console.log(location)
})
}
function error(err) {
console.log(err)
}
</script>
</body>
</html>
并使用jQuery在页面上显示此数据
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title></title>
<script type="text/javascript" src="https://code.jquery.com/jquery-2.2.3.js"></script>
</head>
<body>
<p>Country: <span id="country"></span></p>
<p>State: <span id="state"></span></p>
<p>City: <span id="city"></span></p>
<p>Address: <span id="address"></span></p>
<p>Latitude: <span id="latitude"></span></p>
<p>Longitude: <span id="longitude"></span></p>
<script type="text/javascript">
navigator.geolocation.getCurrentPosition(success, error);
function success(position) {
var GEOCODING = 'https://maps.googleapis.com/maps/api/geocode/json?latlng=' + position.coords.latitude + '%2C' + position.coords.longitude + '&language=en';
$.getJSON(GEOCODING).done(function(location) {
$('#country').html(location.results[0].address_components[5].long_name);
$('#state').html(location.results[0].address_components[4].long_name);
$('#city').html(location.results[0].address_components[2].long_name);
$('#address').html(location.results[0].formatted_address);
$('#latitude').html(position.coords.latitude);
$('#longitude').html(position.coords.longitude);
})
}
function error(err) {
console.log(err)
}
</script>
</body>
</html>
这是我的更新的工作版本,它将得到City / Town,看来json响应中的某些字段已修改。请参考先前针对此问题的答案。(感谢Michal和另外一个参考:Link
var geocoder;
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(successFunction, errorFunction);
}
// Get the latitude and the longitude;
function successFunction(position) {
var lat = position.coords.latitude;
var lng = position.coords.longitude;
codeLatLng(lat, lng);
}
function errorFunction() {
alert("Geocoder failed");
}
function initialize() {
geocoder = new google.maps.Geocoder();
}
function codeLatLng(lat, lng) {
var latlng = new google.maps.LatLng(lat, lng);
geocoder.geocode({latLng: latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[1]) {
var arrAddress = results;
console.log(results);
$.each(arrAddress, function(i, address_component) {
if (address_component.types[0] == "locality") {
console.log("City: " + address_component.address_components[0].long_name);
itemLocality = address_component.address_components[0].long_name;
}
});
} else {
alert("No results found");
}
} else {
alert("Geocoder failed due to: " + status);
}
});
}
geolocator.js可以做到这一点。(我是作者)。
获取城市名称(受限地址)
geolocator.locateByIP(options, function (err, location) {
console.log(location.address.city);
});
获取完整的地址信息
下面的示例将首先尝试使用HTML5 Geolocation API来获取确切的坐标。如果失败或被拒绝,它将回退到Geo-IP查找。获取坐标后,会将坐标反向地理编码到一个地址中。
var options = {
enableHighAccuracy: true,
fallbackToIP: true, // fallback to IP if Geolocation fails or rejected
addressLookup: true
};
geolocator.locate(options, function (err, location) {
console.log(location.address.city);
});
这在内部使用Google API(用于地址查找)。因此,在进行此调用之前,您应该使用Google API密钥配置geolocator。
geolocator.config({
language: "en",
google: {
version: "3",
key: "YOUR-GOOGLE-API-KEY"
}
});
Geolocator支持地理位置(通过HTML5或IP查找),地理编码,地址查找(反向地理编码),距离和持续时间,时区信息以及更多功能...
经过一些搜索和拼凑了几个不同的解决方案以及我自己的东西之后,我想到了这个函数:
function parse_place(place)
{
var location = [];
for (var ac = 0; ac < place.address_components.length; ac++)
{
var component = place.address_components[ac];
switch(component.types[0])
{
case 'locality':
location['city'] = component.long_name;
break;
case 'administrative_area_level_1':
location['state'] = component.long_name;
break;
case 'country':
location['country'] = component.long_name;
break;
}
};
return location;
}
您可以使用https://ip-api.io/来获取城市名称。它支持IPv6。
作为奖励,它允许检查ip地址是tor节点,公共代理还是垃圾邮件发送者。
JavaScript代码:
$(document).ready(function () {
$('#btnGetIpDetail').click(function () {
if ($('#txtIP').val() == '') {
alert('IP address is reqired');
return false;
}
$.getJSON("http://ip-api.io/json/" + $('#txtIP').val(),
function (result) {
alert('City Name: ' + result.city)
console.log(result);
});
});
});
HTML代码
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<div>
<input type="text" id="txtIP" />
<button id="btnGetIpDetail">Get Location of IP</button>
</div>
JSON输出
{
"ip": "64.30.228.118",
"country_code": "US",
"country_name": "United States",
"region_code": "FL",
"region_name": "Florida",
"city": "Fort Lauderdale",
"zip_code": "33309",
"time_zone": "America/New_York",
"latitude": 26.1882,
"longitude": -80.1711,
"metro_code": 528,
"suspicious_factors": {
"is_proxy": false,
"is_tor_node": false,
"is_spam": false,
"is_suspicious": false
}
}
正如@PirateApp在他的评论中提到的那样,明确地反对Google的Maps API许可来按预期使用Maps API。
您有许多选择,包括下载Geoip数据库并在本地查询它,或使用第三方API服务(例如我的服务ipdata.co)。
ipdata可为您提供来自任何IPv4或IPv6地址的地理位置,组织,货币,时区,呼叫代码,标志和Tor出口节点状态数据。
并具有10个全局端点的可扩展性,每个端点每秒能够处理10,000个以上的请求!
此答案使用的“测试” API密钥非常有限,仅用于测试几个调用。注册您自己的免费API密钥,每天最多可获得1500个开发请求。
$.get("https://api.ipdata.co?api-key=test", function(response) {
$("#ip").html("IP: " + response.ip);
$("#city").html(response.city + ", " + response.region);
$("#response").html(JSON.stringify(response, null, 4));
}, "jsonp");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<h1><a href="https://ipdata.co">ipdata.co</a> - IP geolocation API</h1>
<div id="ip"></div>
<div id="city"></div>
<pre id="response"></pre>
小提琴 https://jsfiddle.net/ipdata/6wtf0q4g/922/
这是另一种解决方法。.向接受的答案中添加更多内容可能会更全面..当然,switch -case将使它看起来更优雅。
function parseGeoLocationResults(result) {
const parsedResult = {}
const {address_components} = result;
for (var i = 0; i < address_components.length; i++) {
for (var b = 0; b < address_components[i].types.length; b++) {
if (address_components[i].types[b] == "street_number") {
//this is the object you are looking for
parsedResult.street_number = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "route") {
//this is the object you are looking for
parsedResult.street_name = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "sublocality_level_1") {
//this is the object you are looking for
parsedResult.sublocality_level_1 = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "sublocality_level_2") {
//this is the object you are looking for
parsedResult.sublocality_level_2 = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "sublocality_level_3") {
//this is the object you are looking for
parsedResult.sublocality_level_3 = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "neighborhood") {
//this is the object you are looking for
parsedResult.neighborhood = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "locality") {
//this is the object you are looking for
parsedResult.city = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "administrative_area_level_1") {
//this is the object you are looking for
parsedResult.state = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "postal_code") {
//this is the object you are looking for
parsedResult.zip = address_components[i].long_name;
break;
}
else if (address_components[i].types[b] == "country") {
//this is the object you are looking for
parsedResult.country = address_components[i].long_name;
break;
}
}
}
return parsedResult;
}
这是一个简单的函数,可以用来获取它。我使用axios发出API请求,但您可以使用其他任何东西。
async function getCountry(lat, long) {
const { data: { results } } = await axios.get(`https://maps.googleapis.com/maps/api/geocode/json?latlng=${lat},${long}&key=${GOOGLE_API_KEY}`);
const { address_components } = results[0];
for (let i = 0; i < address_components.length; i++) {
const { types, long_name } = address_components[i];
if (types.indexOf("country") !== -1) return long_name;
}
}
文章标签:geolocation , html , javascript
版权声明:本文为原创文章,版权归 javascript 所有,欢迎分享本文,转载请保留出处!
评论已关闭!